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The excessive nesting of conditional clauses pushes the code out into an arrow formation:
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And you know you're definitely in trouble when the code you're reading is regularly exceeding the right margin on a typical 1280x1024 display. This is the Arrow Anti-Pattern in action.
One of my primary refactoring tasks is "flattening" arrow code like this. Those sharp, pointy barbs are dangerous! Arrow code has a high cyclomatic complexity value-- a measure of how many distinct paths there are through code:
Studies show a correlation between a program's cyclomatic complexity and its error frequency. A low cyclomatic complexity contributes to a program's understandability and indicates it is amenable to modification at lower risk than a more complex program. A module's cyclomatic complexity is also a strong indicator of its testability.
Where appropriate, I flatten that arrow code by doing the following:
- Replace conditions with guard clauses. This code..
- if (SomeNecessaryCondition) {
- // function body code
- }
if (!SomeNecessaryCondition)
{
throw new RequiredConditionMissingException;
}
// function body code
- Decompose conditional blocks into seperate functions. In the above example, we're in a do..while loop which could be decomposed:
- do
- {
- ValidateRowAttribute(drc[rowIdx]);
- rowIdx++;
- }
- while(rowIdx < rowCount && GetIdAsInt32(drc[rowIdx]) == Id);
- Convert negative checks into positive checks. As a broad rule, I prefer to put the positive comparison first and let the negative comparison fall out naturally into the else clause. I think this reads a lot better and, more importantly, avoids the "I ain't not doing that" syndrome:
- if (Attributes[attrVal.AttributeClassId] is ArrayList)
- {
- // do stuff
- }
- else
- {
- // do stuff
- }
- Always opportunistically return as soon as possible from the function. Once your work is done, get the heck out of there! This isn't always possible -- you might have resources you need to clean up. But whatever you do, you have to abandon the ill-conceived idea that there should only be one exit point at the bottom of the function.
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